Screw Machine Shop, Franklin Park Illinois? (Category: Other - US Local Businesses)
There are but they are hard to find. Look into getting a long-term type of contract with someone so they know thay can rely on you over the long-run. Sell yourself not on the lowest qoute, but in your quality and customer service. People will pay more for thiose although there are always many who only focus on the short term cheapest price-which usually gets them crappy quality. Good luck.
in illinois can i collect unemployment if i quit my job due to extreme heat in the machine shop (Category: Other - US Local Businesses)
I won't say it's impossible, but I have to warn you that you give up a lot of your rights when you decide to quit. You definitely should file for unemployment compensation, however, and see if the company fights it. They might not.
If they do contest unemployment, quitting makes you start out with two strikes against you. Unemployment compensation is supposed to pay when you lose your job through no action of your own. If you get fired for breaking a company rule (like coming in late or leaving early), you can be denied unemployment comp because that is your own action. And similarly, if you quit, that's also your action.
You will have to argue to the hearing examiner that you were effectively fired because the working conditions were so intolerable. That's a tough case, but not necessarily impossible. Was there any way the company could have made the working environment more tolerable? Did you ask them to do those things, maybe opening windows or installing fans? If you asked and they refused, that will help your case. It might also help if you have a doctor's note saying that the working conditions were dangerous to your health.
And maybe the company won't even dispute the claim. If you have otherwise been a good employee, they may not want to make a big case out of the fact that you couldn't continue to work there. And if your job was making you take a lot of sick leave for doctor's visits, they may decide that it is better to pay the unemployment compensation taxes than it is to keep paying you for medical costs and sick days. That sort of thing happens a lot.
Bottom line: File the claim and take your chances. If the company decides to fight it, get as much info together as you can, like the doctor's note and anything you can say about the company making the environment unsafe to work because of the extreme heat. You might not win, but you have nothing to lose here.
Good luck!!
Scenario: Lets say they fire me, am i eliglibe for unemployment benefits in Illinois? (Category: Insurance)
what are chances of winning a counter law suit re:consumer fraud against a tattoo shop? (Category: Other - Entertainment)
a good lawyer for you would help a lot.
What is the pay for an entry level machinist job in illinois? (Category: Other - Careers & Employment)
Ask around at other machine shops and factories. It should be a little higher I think. Try to get a union job. I know that maybe tough though. And some training would also help.
Can you at least guess the problem? I have trying for long adn couln't get the resonable answer. Thank you. (Category: Homework Help)
1) Newton's Law of Cooling says that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature - "ambient temperature" being the temperature of the surroundings. I'm assuming you're not in calculus, so this translates to
T(t) = Ta - (Ta - T0)e^(-kt)
where Ta is the ambient temperature, T0 is the original temperature of the object, k is a constant and t is the time. At t = 0, the exponential becomes 1 and the equation reduces to
T(0) = Ta - Ta + T0 = T0
As t approaches infinity, the exponential approaches 0 and the equation reduces to
T(inf) = Ta - 0 = Ta
Now: You're told that Ta = 65. At t = 10, T = 35, so
T(10) = T0 - (65 - T0)e^(-10k) = 35
You have two unknowns - T0 and k.
You're also told that at t = 20, T = 50, so
T(20) = T0 - (65 - T0)e^(-20k)
You now have two equations in two unknowns. This can be solved.
To help you solve it, note that e^(-20k) = (e^(-10k))^2
2) Radioactive decay follows an exponential pattern. You know that
A(t) = A e^(-kt)
where A(t) is the activity as a function of time, A is the initial activity, t is time and k is the decay constant. You also know that k = ln(2)/t(1/2)
where t(1/2) is the half life. Do a quick web search for the half-life of carbon-14 and use that to find k. Then, you know that at the time you want, A(t) = .17A. So,
.17A = A e^(-kt)
.17 = e^(-kt)
Once you know k, you have only one unknown, that being t. Solve for t, and plug and chug an answer.
I have been trying this problem for long and couln't get it. Can you help me get this calculus problem? (Category: Mathematics)
u(x) = T + (I-T)e^kx
where u(x) = temperature at time x
T = Temperature of the medium
I = the initial temperature
k = the cooling rate
x = the cooling time.
Start with the first "after 10 minutes":
50 = 65 + (35 - 65)e^k10
-15 = -30e^k10
0.5 = e^k10
take natural logs
-0.6931 = 10k
k = -0.06931
Now you can solve for the original temperature
50 = 65 + (I - 65)e^-0.06931 X 20
-15/(I - 65) = 0.25
-15 = .25I - 16.25
.25I = 1.25
I = 5
Can you please help me with this problem? (Category: Mathematics)
Unless you're expected to actually know physics, you can assume that aluminum beams and pretty much anything else will vary linearly with time and the difference between its temperature and room temperature. So, if room temperature is 65, then dTemp / dTime is 65 - Original Temperature times some constant reflecting the physics you don't have to know. I'll call dTemp / dTime " dF/dT" for short, I'll call Original Temperature "OT" for short, and I'll call the extra constant "k" for short.
So we know that after ten minutes, the beam was at 35 degrees. That means that int{t from 0 to 10} of [(k)(65 - OT)*t] = 35. The integrand is (t^2)/2, so plugging in numbers, ((10^2)/2)(k)(35-OT) = 35. This simplifies to k(65-OT) = (35/50), so k(65 - OT) = (7/10). Let's leave that there for a moment.
After twenty minutes, the beam was at 50 degrees. The 'original temperature' now, though, is up to 35 degrees, so I've replaced "OT" with "35". That means that int{t from 10 to 20} of [(k)(65 - 35)*t] = 50. The integrand of "t" is still "(t^2)/2". So plugging in numbers, (((20^2)/2) - ((10^2)/2)))(k)(65-35) = 50. This simplifies to (200-50)(k)(30) = 50, which simplifies to (90)(k) = 1. Another way of putting that is that k = (1/90).
Now that we know "k", we can plug it back into the thing that we put on hold for a minute: k(65 - OT) = (7/10). This now becomes (1/90)(65-OT) = (7/10). We're done with the calculus; the rest is algebra. You should be able to solve this equation to get the value of OT. One nice sign that we've been doing the work properly is that OT turns out to be a nice 'even' number.
The second problem uses pretty much the same ideas; you just have to keep in mind that when carbon-14 or anything else radioactively decays in a math class, it does so at the rate of (1/(e^[half-life])), where e is a special constant you can find on your calculator that winds up being something like 2.57, and the half-life of an element is a constant that you can look up in your chemistry textbook, physics textbook, or maybe online. I believe the half-life of carbon-14 is a few hundred thousand years, but I could be wrong. If the animal died in A.D. 0, and the half-life was a thousand years, then in AD 2000 there would be (1/e^2) left of the carbon. (1/2.57^2) is about 12%. Since the answer's 17%, I must be wrong about either when the animal died or what the half-life of carbon-14 is. So go look up the half-life of carbon-14, and then use calculus to save time on your guess-and-check. Good luck!
Commercial Coffee Machines? (Category: Other - Food & Drink)
I used to own a coffee shop, so I feel your pain. Yes there are commercial grade machines that will brew small amounts of coffee. I don't know where to buy them, but strangely, at some of the rest areas in Illinois, there are machines that will brew a single cup of coffee at a time, with freshly ground beans. These things were awesome. They were really fast, too. I don't have clue as to who makes them, but at least we know that it can be done. If you are grinding flavored coffee beans (vanilla or whatever) using a burr grinder, then you will want to use a separate grinder for each one, or your flavors will not be "pure". If you are using a blade type grinder, then you should be ok on flavor by brushing it out after each use.
As far as brewing time, it should be relatively fast, but the strength of flavor can be adjusted a little bit by finer grinding.
I know that this is really confusing. There are lots of good resources on-line, so just keep searching!!!
How much money should I bring to Vegas? (Category: Las Vegas)
Drinks are expensive pretty much everywhere, and especially in the clubs. A mixed drink will run you $8-15, depending on the drink and the club. If you do bottle service at a club, it's a few hundred dollars. Mixed drinks by the pool are about the same at most hotels.
You can get the big yards of frozen drinks for a reasonable price out on the strip - Rockhouse Bar in front of Imperial Palace has them, as does the Carnaval Court at Harrah's.
It's usually advised that you take around $200 per day for food and drinks, but if you plan to drink a lot and eat well then you might watn to bump that up a bit.
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